125^1/2=(2/10)^x+1

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Solution for 125^1/2=(2/10)^x+1 equation: 



125^1/2=(2/10)^x+1

We move all terms to the left:

125^1/2-((2/10)^x+1)=0



Domain of the equation: 10)^x+1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+2/10)^x+1)+125^1/2=0

We calculate fractions


1)*2)+1250x^2/10^x+1)*2)+()/10^x=0

We can not solve this equation

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